Find the equation in standard form of the parabola described.
-The focus has coordinates (-15, 0), and the equation of the directrix is x = 15.
A) $y ^ { 2 } = 60 x$
B) $y ^ { 2 } = - 60 x$
C) $x ^ { 2 } = - 60 y$
D) $y ^ { 2 } = - 15 x$

Question

Find the equation in standard form of the parabola described.
-The focus has coordinates (-15, 0), and the equation of the directrix is x = 15. 
A) $y ^ { 2 } = 60 x$
B) $y ^ { 2 } = - 60 x$
C) $x ^ { 2 } = - 60 y$
D) $y ^ { 2 } = - 15 x$

Quizplus · Accepted Answer

The parabola opens to the left because the focus is to the left of the directrix. The vertex is at the midpoint between the focus and directrix, which is at the origin (0,0). The distance from the vertex to the focus is 15, so $4p = -60$, giving the equation $y^2 = -60x$.

Find the Equation in Standard Form of the Parabola Described y2=60xy ^ { 2 } = 60 xy2=60x

Find the Equation in Standard Form of the Parabola Described $y ^ { 2 } = 60 x$