Solve the problem.
-The diagonal of the floor of a rectangular office cubicle is 2 feet longer than the length of the cubicle and 5 feet longer than twice the width. Find the dimensions of the cubicle. Round to the nearest tenth, if necessary.
A)width: 9.7 feet, length: 22.4 feet
B)width: 4 feet, length: 11 feet
C)width: 3.9 feet, length: 9.7 feet
D)width: 2 feet, length: 9 feet

Question

Quizplus · Accepted Answer

Using the Pythagorean theorem, let the width be $w$ and the length be $l$. The diagonal is $l + 2$ and also $2w + 5$. Setting up equations: $l^2 + w^2 = (l + 2)^2$ and $l^2 + w^2 = (2w + 5)^2$. Solving these equations gives the dimensions as width: 9.7 feet and length: 22.4 feet.

Solve the Problem. -The Diagonal of the Floor of a Rectangular Office Cubicle