Rewrite the series using summation notation. Use 1 as the lower limit of summation.
-$$3 + \frac { 3 ^ { 2 } } { 2 } + \frac { 3 ^ { 3 } } { 3 } + \ldots + \frac { 3 ^ { n } } { n }$$
A) $\sum _ { i = 1 } ^ { n } \frac { 3 ^ { n } } { i }$
B) $\sum _ { i = 1 } ^ { n } \frac { 3 i } { i }$
C) $\sum _ { i = 1 } ^ { n } \frac { 3 ^ { i } } { i }$
D) $\sum _ { i = 1 } ^ { 3 } \frac { 3 ^ { i } } { i }$

Question

Quizplus · Accepted Answer

The series can be expressed in summation notation as the sum from $i = 1$ to $n$ of $\frac{3^i}{i}$, which matches option C. Each term of the series is of the form $\frac{3^i}{i}$, where $i$ represents the position of the term in the series.

Rewrite the Series Using Summation Notation 3+322+333+…+3nn3 + \frac { 3 ^ { 2 } } { 2 } + \frac { 3 ^ { 3 } } { 3 } + \ldots + \frac { 3 ^ { n } } { n }3+232​+333​+…+n3n​

Rewrite the Series Using Summation Notation $3 + \frac { 3 ^ { 2 } } { 2 } + \frac { 3 ^ { 3 } } { 3 } + \ldots + \frac { 3 ^ { n } } { n }$