$\left. (- 7 x ^ { 3 } y ^ { 4 } \right) ^ { 2 }$
A) $49 x ^ { 5 } y ^ { 6 }$
B) $- 7 x ^ { 6 } y ^ { 8 }$
C) $49 x ^ { 6 } y ^ { 8 }$
D) $- 49 \mathrm { x } ^ { 6 } \mathrm { y } ^ { 8 }$

Question

Quizplus · Accepted Answer

When you square the term $(-7x^3y^4)^2$, you square each component: $(-7)^2 = 49$, $x^3$ squared becomes $x^6$, and $y^4$ squared becomes $y^8$, resulting in $49x^6y^8$.

(−7x3y4)2\left. (- 7 x ^ { 3 } y ^ { 4 } \right) ^ { 2 }(−7x3y4)2

$\left. (- 7 x ^ { 3 } y ^ { 4 } \right) ^ { 2 }$