Solve the system. If there is no solution or if the system's equations are dependent, so state.
-$$\left\{ \begin{array} { r r }
x + y + z = & 2 \
x - y - 2 z = & - 10 \
3 x + 3 y + 3 z = & 6
\end{array} \right.$$
A) infinitely many solutions; dependent equations
B) $\{ ( - 4,4,2 ) \}$
C) no solution or $\varnothing$
D) $\{ ( - 4,2,4 ) \}$

Question

Solve the system. If there is no solution or if the system's equations are dependent, so state.
-$$\left\{ \begin{array} { r r } 
x + y + z = & 2 \
x - y - 2 z = & - 10 \
3 x + 3 y + 3 z = & 6
\end{array} \right.$$
A) infinitely many solutions; dependent equations
B) $\{ ( - 4,4,2 ) \}$
C) no solution or $\varnothing$
D) $\{ ( - 4,2,4 ) \}$

Quizplus · Accepted Answer

The Answer of Solve the system. If there is no solution or if the system's equations are dependent, so state.
-$$\left\{ \begin{array} { r r } 
x + y + z = & 2 \
x - y - 2 z = & - 10 \
3 x + 3 y + 3 z = & 6
\end{array} \right.$$
A) infinitely many solutions; dependent equations
B) $\{ ( - 4,4,2 ) \}$
C) no solution or $\varnothing$
D) $\{ ( - 4,2,4 ) \}$

Solve the System {x+y+z=2x−y−2z=−103x+3y+3z=6\left\{ \begin{array} { r r } x + y + z = & 2 \\x - y - 2 z = & - 10 \\3 x + 3 y + 3 z = & 6\end{array} \right.⎩⎨⎧​x+y+z=x−y−2z=3x+3y+3z=​2−106​

Solve the System $\left\{ \begin{array} { r r } x + y + z = & 2 \\x - y - 2 z = & - 10 \\3 x + 3 y + 3 z = & 6\end{array} \right.$