Solve the system by the addition method.
-$$\left\{ \begin{array} { l }
3 x + 6 y = 3 \
2 x + 9 y = - 8
\end{array} \right.$$
A) $\{ ( - 5,2 ) \}$
B) $\{ ( x , y ) \mid 3 x + 6 y = 3 \}$
C) $\{ ( 5 , - 2 ) \}$
D) $\varnothing$

Question

Solve the system by the addition method.
-$$\left\{ \begin{array} { l } 
3 x + 6 y = 3 \
2 x + 9 y = - 8
\end{array} \right.$$
A) $\{ ( - 5,2 ) \}$
B) $\{ ( x , y ) \mid 3 x + 6 y = 3 \}$
C) $\{ ( 5 , - 2 ) \}$
D) $\varnothing$

Quizplus · Accepted Answer

By multiplying the first equation by 3 and the second by 2, we can eliminate $y$ and solve for $x$, leading to the solution $x = 5$ and $y = -2$.

Solve the System by the Addition Method {3x+6y=32x+9y=−8\left\{ \begin{array} { l } 3 x + 6 y = 3 \\2 x + 9 y = - 8\end{array} \right.{3x+6y=32x+9y=−8​

Solve the System by the Addition Method $\left\{ \begin{array} { l } 3 x + 6 y = 3 \\2 x + 9 y = - 8\end{array} \right.$