Solve.
-When a number is subtracted from -7, the absolute value of the difference is more than 3. Use interval notation to express the set of all numbers that satisfy this condition.
A) $( \infty , - 4 ) \cup ( 10 , \infty )$
B) $( \infty , - 10 ) \cup ( - 4 , \infty )$
C) $( \infty , - 10 ] \cup [ - 4 , \infty )$
D) $( - 10 , - 4 )$

Question

Solve.
-When a number is subtracted from -7, the absolute value of the difference is more than 3. Use interval notation to express the set of all numbers that satisfy this condition. 
A) $( \infty , - 4 ) \cup ( 10 , \infty )$
B) $( \infty , - 10 ) \cup ( - 4 , \infty )$
C) $( \infty , - 10 ] \cup [ - 4 , \infty )$
D) $( - 10 , - 4 )$

Quizplus · Accepted Answer

The condition can be written as $|x + 7| > 3$, which leads to two cases: $x + 7 > 3$ and $x + 7 < -3$. Solving these gives $x > -10$ and $x < -4$, respectively. Combining these intervals gives the solution $( \infty , - 10 ) \cup ( - 4 , \infty )$.

Solve -When a Number Is Subtracted from -7, the Absolute (∞,−4)∪(10,∞)( \infty , - 4 ) \cup ( 10 , \infty )(∞,−4)∪(10,∞)

Solve
-When a Number Is Subtracted from -7, the Absolute $( \infty , - 4 ) \cup ( 10 , \infty )$