Multiply using the rule for the product of the sum and difference of two terms. Assume any variable exponents represent whole numbers.
-$$( 6 x + 11 ) ( 6 x - 11 )$$
A) $x ^ { 2 } - 121$
B) $36 x ^ { 2 } - 132 x - 121$
C) $36 x ^ { 2 } + 132 x - 121$
D) $36 \mathrm { x } ^ { 2 } - 121$

Question

Quizplus · Accepted Answer

The product of the sum and difference of two terms is given by the formula $(a + b)(a - b) = a^2 - b^2$. Applying this to the given expression, we get $36x^2 - 121$.

Multiply Using the Rule for the Product of the Sum (6x+11)(6x−11)( 6 x + 11 ) ( 6 x - 11 )(6x+11)(6x−11)

Multiply Using the Rule for the Product of the Sum $( 6 x + 11 ) ( 6 x - 11 )$