Find the product. Assume all variable exponents represent whole numbers.
-$$( x y - 7 ) \left( x ^ { 2 } y ^ { 2 } + 2 x y + 6 \right)$$
A) $x ^ { 3 } y ^ { 3 } + 2 x ^ { 2 } y ^ { 2 } + 6 x y$
B) $x ^ { 3 } y ^ { 3 } + 9 x ^ { 2 } y ^ { 2 } + 20 x y + 42$
C) $7 x ^ { 3 } y ^ { 3 } - 14 x ^ { 2 } y ^ { 2 } - 42 x y$
D) $x ^ { 3 } y ^ { 3 } - 5 x ^ { 2 } y ^ { 2 } - 8 x y - 42$

Question

Quizplus · Accepted Answer

To find the product, distribute each term in the first polynomial across the second polynomial: $(xy)(x^2y^2) + (xy)(2xy) + (xy)(6) - 7(x^2y^2) - 7(2xy) - 7(6)$. This simplifies to $x^3y^3 + 2x^2y^2 + 6xy - 7x^2y^2 - 14xy - 42$, which further simplifies to $x^3y^3 - 5x^2y^2 - 8xy - 42$.

Find the Product (xy−7)(x2y2+2xy+6)( x y - 7 ) \left( x ^ { 2 } y ^ { 2 } + 2 x y + 6 \right)(xy−7)(x2y2+2xy+6)

Find the Product $( x y - 7 ) \left( x ^ { 2 } y ^ { 2 } + 2 x y + 6 \right)$