Find the product. Assume all variable exponents represent whole numbers.
-$$( x + 3 ) \left( 6 x ^ { 2 } + 2 x + 5 \right)$$
A) $24 x ^ { 3 } + 8 x ^ { 2 } + 20 x$
B) $36 x ^ { 4 } + 6 x ^ { 3 } + 30 x ^ { 2 } + 15$
C) $6 x ^ { 3 } + 18 x ^ { 2 } + 6 x + 15$
D) $6 x ^ { 3 } + 20 x ^ { 2 } + 11 x + 15$

Question

Quizplus · Accepted Answer

To find the product, distribute each term in the first polynomial across the second polynomial: $(x + 3)(6x^2 + 2x + 5) = x(6x^2) + x(2x) + x(5) + 3(6x^2) + 3(2x) + 3(5)$, which simplifies to $6x^3 + 2x^2 + 5x + 18x^2 + 6x + 15$, combining like terms gives $6x^3 + 20x^2 + 11x + 15$.

Find the Product (x+3)(6x2+2x+5)( x + 3 ) \left( 6 x ^ { 2 } + 2 x + 5 \right)(x+3)(6x2+2x+5)

Find the Product $( x + 3 ) \left( 6 x ^ { 2 } + 2 x + 5 \right)$