Solve the Problem $A = \frac { 1 } { 2 } b h$

Solve the problem.
-If the formula for the area of a triangle, $A = \frac { 1 } { 2 } b h$ , is solved for $h$ , then $h = \frac { 2 A } { b }$ . Use this formula to find $h$ if area A is $\frac { 2 y + 1 } { 8 }$ square feet and base $b$ is $\frac { 3 y - 5 } { 11 }$ feet. Write $h$ in simplified form.

A) $\frac { 4 ( 3 y - 5 ) } { 11 ( 2 y + 1 ) } \mathrm { ft }$
B) $\frac { ( 2 \mathrm { y } + 1 ) ( 3 \mathrm { y } - 5 ) } { 44 } \mathrm { ft }$
C) $\frac { 11 ( 2 y + 1 ) } { 8 ( 3 y - 5 ) } \mathrm { ft }$
D) $\frac { 11 ( 2 y + 1 ) } { 4 ( 3 y - 5 ) } \mathrm { ft }$