Solve the problem.
-Jacie is considering a job that offers a monthly starting salary of $3500 and guarantees her a monthly raise of $110 during her first year on the job. Find the general term of this arithmetic sequence and her monthly salary at the end of her first year.
A) $a _ { n } = 3390 + 110 n$; $\$ 4710$
B) $a _ { n } = 3500 + 110 n ; \$ 4820$
C) $a _ { n } = 3500 + 110 n ; \$ 4710$
D) $a _ { n } = 3390 + 110 ( n - 1 ) ; \$ 4600$

Question

Solve the problem.
-Jacie is considering a job that offers a monthly starting salary of $3500 and guarantees her a monthly raise of $110 during her first year on the job. Find the general term of this arithmetic sequence and her monthly salary at the end of her first year. 
A) $a _ { n } = 3390 + 110 n$; $\$ 4710$
B) $a _ { n } = 3500 + 110 n ; \$ 4820$
C) $a _ { n } = 3500 + 110 n ; \$ 4710$
D) $a _ { n } = 3390 + 110 ( n - 1 ) ; \$ 4600$

Quizplus · Accepted Answer

The general term of an arithmetic sequence is given by $a_n = a_1 + (n - 1)d$, where $a_1$ is the first term, $d$ is the common difference, and $n$ is the term number. Here, $a_1 = 3500$ and $d = 110$, but the formula in choice A mistakenly uses 3390 as the starting value. However, to calculate the salary at the end of the first year (12th month), we use $a_{12} = 3500 + (12 - 1) \times 110 = 3500 + 11 \times 110 = 4710$, which matches the outcome in A despite the initial term discrepancy in the formula. The correct formula should be $a_n = 3500 + 110(n - 1)$, but due to the options provided and the correct final salary, A is chosen based on the end salary match. My explanation contains an error in selecting the correct choice based on the initial premise; the correct formula and end salary align with option C, not A, as initially stated.

Solve the Problem an=3390+110na _ { n } = 3390 + 110 nan​=3390+110n

Solve the Problem $a _ { n } = 3390 + 110 n$