Choose the one alternative that best completes the statement or answers the question.
-Four different watering schedules are used on bean plants. The number of beans on each randomly selected plant is given below. Use the Kruskal-Wallis test to find the critical value $\chi ^ { 2 }$ to test the hypothesis that there is no difference in the distribution of the populations. Use $\alpha = 0.05$.
$\begin{array}{cccc}
\hline \text { Schedule 1 } & \text { Schedule2 } & \text { Schedule 3 } & \text { Schedule 4 } \
\hline 10 & 9 & 10 & 7 \
9 & 12 & 7 & 9 \
10 & 9 & 8 & 7 \
11 & 9 & 7 & 8 \
11 & 9 & 6 & 9 \
10 & 10 & 7 & 8 \
\hline
\end{array}$
A) $7.815$
B) $7.352$
C) $6.531$
D) $5.198$

Question

Choose the one alternative that best completes the statement or answers the question.
-Four different watering schedules are used on bean plants. The number of beans on each randomly selected plant is given below. Use the Kruskal-Wallis test to find the critical value $\chi ^ { 2 }$ to test the hypothesis that there is no difference in the distribution of the populations. Use $\alpha = 0.05$.
$\begin{array}{cccc}
\hline \text { Schedule 1 } & \text { Schedule2 } & \text { Schedule 3 } & \text { Schedule 4 } \
\hline 10 & 9 & 10 & 7 \
9 & 12 & 7 & 9 \
10 & 9 & 8 & 7 \
11 & 9 & 7 & 8 \
11 & 9 & 6 & 9 \
10 & 10 & 7 & 8 \
\hline
\end{array}$
A) $7.815$ 
B) $7.352$
C) $6.531$
D) $5.198$

Quizplus · Accepted Answer

The Kruskal-Wallis test is used to determine if there are statistically significant differences between the distributions of two or more independent samples. The critical value for the Kruskal-Wallis test is found in the chi-square ($\chi^2$) distribution table. Given the significance level ($\alpha$) of 0.05 and the degrees of freedom (df) for the Kruskal-Wallis test, which is the number of groups minus one (in this case, 4 - 1 = 3), the critical value from the chi-square distribution table for $\alpha = 0.05$ and $df = 3$ is $7.815$.

Choose the One Alternative That Best Completes the Statement or Answers