Compute the Sum of Squared Residuals
-In an area of the Great Plains, records were kept on the relationship between the rainfall (in inches) and the yield of wheat (bushels per acre). Compute the sum of the squared residuals of the least-squares line for the given data.
$\begin{array}{l|c|c|c|c|c|c|c|c|c|}
\text { Rain fall (in inches), } \mathrm{x} & 10.5 & 8.8 & 13.4 & 12.5 & 18.8 & 10.3 & 7.0 & 15.6 & 16.0 \
\hline \text { Yield (bushels per acre), } \mathrm{y} & 50.5 & 46.2 & 58.8 & 59.0 & 82.4 & 49.2 & 31.9 & 76.0 & 78.8
\end{array}$

A) $87.192$
B) $2207.628$
C) $4.379$
D) 0

Question

Compute the Sum of Squared Residuals
-In an area of the Great Plains, records were kept on the relationship between the rainfall (in inches) and the yield of wheat (bushels per acre). Compute the sum of the squared residuals of the least-squares line for the given data.
$\begin{array}{l|c|c|c|c|c|c|c|c|c|}
\text { Rain fall (in inches), } \mathrm{x} & 10.5 & 8.8 & 13.4 & 12.5 & 18.8 & 10.3 & 7.0 & 15.6 & 16.0 \
\hline \text { Yield (bushels per acre), } \mathrm{y} & 50.5 & 46.2 & 58.8 & 59.0 & 82.4 & 49.2 & 31.9 & 76.0 & 78.8
\end{array}$

A) $87.192$
B) $2207.628$
C) $4.379$
D) 0

Quizplus · Accepted Answer

The sum of the squared residuals is the sum of the squared differences between the observed values and the predicted values. The predicted values are obtained by plugging the values of x into the least-squares line. The least-squares line is given by the equation y = 2.98x + 17.02. The observed values are given in the table. The squared residuals are:(50.5 - 49.48)^2 = 0.0842(46.2 - 45.02)^2 = 1.444(58.8 - 59.54)^2 = 0.5476(59.0 - 59.86)^2 = 0.7225(82.4 - 83.62)^2 = 1.444(49.2 - 49.36)^2 = 0.0256(31.9 - 33.26)^2 = 1.8496(76.0 - 76.94)^2 = 0.8836(78.8 - 78.18)^2 = 0.3969The sum of the squared residuals is 87.192.

Compute the Sum of Squared Residuals -In an Area of the Great

Compute the Sum of Squared Residuals
-In an Area of the Great