Provide an appropriate response.
-The average score of all golfers for a particular course has a mean of 66 and a standard deviation of 5 . Suppose 100 golfers played the course today. Find the probability that the average score of the 100 golfers exceeded $67 .$
A) $0.0228$
B) $0.1293$
C) $0.4772$
D) $0.3707$

Question

Quizplus · Accepted Answer

To find the probability that the average score of the 100 golfers exceeded 67, we use the formula for the z-score: $z = \frac{\bar{x} - \mu}{\sigma/\sqrt{n}}$, where $\bar{x}$ is the sample mean, $\mu$ is the population mean, $\sigma$ is the population standard deviation, and $n$ is the sample size. Plugging in the values, we get $z = \frac{67 - 66}{5/\sqrt{100}} = \frac{1}{0.5} = 2$. Looking up 2 in the z-table gives us the area to the left, which is 0.9772. To find the probability of exceeding 67, we subtract this from 1, giving $1 - 0.9772 = 0.0228$.

Provide an Appropriate Response 67.67 .67. A) 0.02280.02280.0228 B) 0.12930.12930.1293 C) 0.47720.47720.4772 D) 0.37070.37070.3707

Provide an Appropriate Response $67 .$ A) $0.0228$ B) $0.1293$ C) $0.4772$ D) $0.3707$