Find an equation of variation for the given situation.
- y varies jointly as x and the square of z , and y=209.9072 when x=0.8 and z=4.6
A) $y = 14.6 \times z ^ { 2 }$
B) $y = 9.92 x ^ { 2 } z ^ { 2 }$
C) $y = 12.4 x z ^ { 2 }$
D) $y = 12.9 x \sqrt { z }$

Question

Find an equation of variation for the given situation.
- y  varies jointly as  x  and the square of  z , and  y=209.9072  when  x=0.8  and  z=4.6 
A) $y = 14.6 \times z ^ { 2 }$
B) $y = 9.92 x ^ { 2 } z ^ { 2 }$
C) $y = 12.4 x z ^ { 2 }$
D) $y = 12.9 x \sqrt { z }$

Quizplus · Accepted Answer

The equation of variation where $y$ varies jointly as $x$ and the square of $z$ is $y = kxz^2$. To find the constant of variation $k$, we use the given values: $y = 209.9072$, $x = 0.8$, and $z = 4.6$. Substituting these values into the equation gives $209.9072 = k \cdot 0.8 \cdot (4.6)^2$. Solving for $k$ gives $k = 12.4$, so the correct equation is $y = 12.4xz^2$.

Find an Equation of Variation for the Given Situation y=14.6×z2y = 14.6 \times z ^ { 2 }y=14.6×z2

Find an Equation of Variation for the Given Situation $y = 14.6 \times z ^ { 2 }$