Find an equation of variation for the given situation.
-y varies inversely as x and y =5.25 when x=0.36
A) $y = \frac { 1.89 } { x }$
B) $y = \frac { 2.29 } { x }$
C) $y = \frac { 14.58 } { x }$
D) y=14.58x

Question

Find an equation of variation for the given situation.
-y varies inversely as  x and y =5.25 when x=0.36 
A) $y = \frac { 1.89 } { x }$
B) $y = \frac { 2.29 } { x }$
C) $y = \frac { 14.58 } { x }$
D) y=14.58x

Quizplus · Accepted Answer

The equation for inverse variation is $y = \frac{k}{x}$, where $k$ is the constant of variation. To find $k$, use the given values: $5.25 = \frac{k}{0.36}$, solving for $k$ gives $k = 1.89$. Therefore, the equation is $y = \frac{1.89}{x}$.

Find an Equation of Variation for the Given Situation y=1.89xy = \frac { 1.89 } { x }y=x1.89​

Find an Equation of Variation for the Given Situation $y = \frac { 1.89 } { x }$