Consider only the discriminant, $b ^ { 2 } - 4 a c$ to determine whether one real-number solution, two different real-number
solutions, or two different imaginary-number solutions exist.
-$$x ^ { 2 } + 4 x + 5 = 0$$
A) Two different real-number solutions
B) One real solution
C) Two different imaginary-number solutions

Question

Quizplus · Accepted Answer

The discriminant for the equation $x^2 + 4x + 5 = 0$ is calculated as $b^2 - 4ac = (4)^2 - 4(1)(5) = 16 - 20 = -4$. Since the discriminant is negative, this means there are two different imaginary-number solutions.

Consider Only the Discriminant b2−4acb ^ { 2 } - 4 a cb2−4ac

Consider Only the Discriminant $b ^ { 2 } - 4 a c$