Solve.
-In 1998 , the population of Country C was 26 million, and the exponential growth rate was $1 \%$ per year. Find the exponential growth function.
A) $\mathrm { P } ( \mathrm { t } ) = 26 \mathrm { e } ^ { 1 \mathrm { t } }$, where $\mathrm { P } ( \mathrm { t } )$ is in millions and $\mathrm { t }$ is the number of years after 1998 .
B) $\mathrm { P } ( \mathrm { t } ) = 26 \mathrm { e } ^ { 0.01 }$, where $\mathrm { P } ( \mathrm { t } )$ is in millions and $\mathrm { t }$ is the number of years after 1998 .
C) $\mathrm { P } ( \mathrm { t } ) = 26 ^ { 0.01 \mathrm { t } }$, where $\mathrm { P } ( \mathrm { t } )$ is in millions and $t$ is the number of years after 1998 .
D) $P ( t ) = 26 e ^ { 0.01 t }$, where $P ( t )$ is in millions and $t$ is the number of years after 1998 .

Question

Quizplus · Accepted Answer

The correct exponential growth function for a population starting at 26 million with a 1% growth rate per year is $P(t) = 26e^{0.01t}$, where $e$ is the base of the natural logarithm, $0.01$ represents the 1% growth rate as a decimal, and $t$ is the number of years after 1998.

Solve -In 1998 , the Population of Country C Was 1%1 \%1%

Solve
-In 1998 , the Population of Country C Was $1 \%$