For the function f, use composition of functions to show that f $\mathrm { f } ^ { - 1 } \text { is as given. }$
-$$f ( x ) = \frac { x - 2 } { 8 } , f ^ { - 1 } ( x ) = 8 x + 2$$

Name: For the function f, use composition of functions to show that f $\mathrm { f } ^ { - 1 } \text { is as given. }$ -\[f ( x ) = \frac { x - 2 } { 8 } , f ^ { - 1 } ( x ) = 8 x + 2\]
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The Answer is Answers may vary. One possible solution is: 1.

\left( f ^ { - 1 } \right.

of

) ( x ) = f ^ { - 1 } ( f ( x ) ) = f ^ { - 1 } ( ( x - 2 ) / 8 ) = 8 ( ( x - 2 ) / 8 ) + 2 = ( x - 2 ) + 2 = x

;
2.

\left( f \circ f ^ { - 1 } \right) ( x ) = f \left( f ^ { - 1 } ( x ) \right) = f ( 8 x + 2 ) = ( ( 8 x + 2 ) - 2 ) / 8 = 8 x / 8 = x

For the Function F, Use Composition of Functions to Show f−1 is as given. \mathrm { f } ^ { - 1 } \text { is as given. }f−1 is as given.

For the Function F, Use Composition of Functions to Show $\mathrm { f } ^ { - 1 } \text { is as given. }$