Find the nth, or general, term.
-$\frac { 1 } { 7 } , \frac { 9 } { 7 } , \frac { 81 } { 7 } , \ldots$
A) $\frac { 1 } { 7 } + 9 ( \mathrm { n } - 1 )$
B) $\frac { 1 } { 7 } ( 9 ) ^ { n - 1 }$
C) $\frac { 1 } { 7 } + \frac { 8 } { 7 } ( \mathrm { n } - 1 )$
D) $\left( \frac { 1 } { 7 } \right) ^ { n - 1 } + \frac { 8 } { 7 }$

Question

Quizplus · Accepted Answer

The sequence is geometric with a common ratio of 9 and a first term of $ \frac{1}{7} $. The nth term of a geometric sequence is given by $ a \cdot r^{n-1} $, where $ a $ is the first term and $ r $ is the common ratio. Therefore, the nth term is $ \frac{1}{7} \cdot 9^{n-1} $.

Find the Nth, or General, Term 17,97,817,…\frac { 1 } { 7 } , \frac { 9 } { 7 } , \frac { 81 } { 7 } , \ldots71​,79​,781​,…

Find the Nth, or General, Term $\frac { 1 } { 7 } , \frac { 9 } { 7 } , \frac { 81 } { 7 } , \ldots$