Find the values of the variables in the equation.
-$$
\left[\begin{array}{crr}
t-1 & -4 & 0 \
-3 & 4 & 3
\end{array}\right]=\left[\begin{array}{lll}
-4 & -4 & 0 \
-3 & x-8 & 3
\end{array}\right]
$$
A) $ t=-3, x=12 $
B) $ t=-4, x=4 $
C) $ \mathrm{t}=-3, \mathrm{x}=-4 $
D) $ t=-4, x=-4 $

Question

Quizplus · Accepted Answer

For two matrices to be equal, their corresponding elements must be equal. Comparing the elements of the given matrices, we get $t - 1 = -4$ and $x - 8 = 4$. Solving these equations gives $t = -3$ and $x = 12$.

Find the Values of the Variables in the Equation [t−1−40−343]=[−4−40−3x−83]\left[\begin{array}{crr}t-1 & -4 & 0 \\-3 & 4 & 3\end{array}\right]=\left[\begin{array}{lll}-4 & -4 & 0 \\-3 & x-8 & 3\end{array}\right][t−1−3​−44​03​]=[−4−3​−4x−8​03​]

Find the Values of the Variables in the Equation $\left[\begin{array}{crr}t-1 & -4 & 0 \\-3 & 4 & 3\end{array}\right]=\left[\begin{array}{lll}-4 & -4 & 0 \\-3 & x-8 & 3\end{array}\right]$