The boom of a crane is 20 m long and is inclined 20° from the horizontal. A bucket of cement with a mass of 3000 kg is suspended from the upper end of the boom. What is the torque acting on the point where the boom is attached to the crane? A)5.5 × 10⁵ N m B)3.5 × 10⁵ N m C)4.5 × 10⁵ N m D)2.0 × 10⁵ N m E)2.0 × 10⁴ N m

Question

Quizplus · Accepted Answer

The torque is given by the product of the force and the perpendicular distance from the point of application of the force to the pivot point. In this case, the force is the weight of the bucket, which is 3000 kg * 9.8 m/s^2 = 29400 N. The perpendicular distance from the point of application of the force to the pivot point is the length of the boom, which is 20 m. Therefore, the torque is 29400 N * 20 m = 5.88 * 10^5 N m.

The Boom of a Crane Is 20 M Long and Is