A steel sphere with a radius of 2.0 m falls off a ship and sinks to a depth where the pressure is 15 MN/m². The bulk modulus for steel is 1.6×10¹¹N/m². What is the change in the radius of the sphere? A)0.021 mm B)4.2 mm C)0.42 mm D)0.19 mm E)0.063 mm

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Quizplus · Accepted Answer

The change in volume due to pressure can be calculated using the formula for bulk modulus: ΔV/V = -ΔP/K. The change in radius can then be derived from the change in volume. Solving gives a change in radius of approximately 0.063 mm.

A Steel Sphere with a Radius of 2