When a mass of 180 g is attached to a vertical spring and lowered to its equilibrium position, it is found that the spring extends 12 cm. If the mass is now displaced from its equilibrium position, what is the period of the resulting oscillations?
A)2.2 s
B)3.7 s
C)0.69 s
D)9.0 s
E)1.5 s

Question

Quizplus · Accepted Answer

The period of oscillation for a mass-spring system is given by T = 2π√(m/k). First, find the spring constant k using Hooke's Law (F = kx), where F = mg and x = 0.12 m. Then, use the mass m = 0.18 kg to find T. The calculation results in approximately 0.69 s.

When a Mass of 180 G Is Attached to a Vertical