How many turns should a 10-cm long solenoid have if it is to generate a 1.5 × 10^-³ T magnetic field on 1.0 A of current? A)12 B)15 C)120 D)1200 E)3200

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The magnetic field inside a solenoid is given by:B = μ₀nIwhere:B is the magnetic field in teslasμ₀ is the permeability of free space (4π × 10^-7 T·m/A)n is the number of turns per unit length in turns/meterI is the current in amperesWe can rearrange this equation to solve for n:n = B / (μ₀I)Plugging in the given values, we get:n = (1.5 × 10^-3 T) / (4π × 10^-7 T·m/A * 1.0 A) = 120 turns/meterTo find the total number of turns, we multiply this by the length of the solenoid:N = nL = 120 turns/meter * 0.10 m = 120 turnsTherefore, the correct answer is C) 120.

How Many Turns Should a 10-Cm Long Solenoid Have If