A 22-μF capacitor is connected across a 120 V (rms) 60 Hz source. What is the peak current in this case?
A)0
B)1.0 A
C)10.0 A
D)0.10 A
E)1.4 A

Question

Quizplus · Accepted Answer

The peak current (I_peak) can be calculated using the formula I_peak = V_peak * ω * C, where V_peak = V_rms * √2, ω = 2πf, and C is the capacitance. For a 120 V (rms) source at 60 Hz with a 22 μF capacitor, I_peak = 120√2 * 2π * 60 * 22 * 10^-6 = 1.4 A.

A 22-μF Capacitor Is Connected Across a 120 V (Rms)