Find the exact value of s in the given interval that has the given circular function value.
-$$\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$$
A) $\mathrm { s } = \frac { 3 \pi } { 4 }$
B) $s = \frac { 5 \pi } { 6 }$
C) $s = \frac { 2 \pi } { 3 }$
D) $s = \frac { \pi } { 4 }$

Question

Quizplus · Accepted Answer

The value of $\sin s = \frac{\sqrt{2}}{2}$ corresponds to an angle of $\frac{\pi}{4}$ or $\frac{3\pi}{4}$ in standard position. Given the interval $\left[\frac{\pi}{2}, \pi\right]$, the correct angle is $\frac{3\pi}{4}$, as it is the only one within the specified range.

Find the Exact Value of S in the Given Interval [π2,π];sin⁡s=22\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }[2π​,π];sins=22​​

Find the Exact Value of S in the Given Interval $\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$