Solve the problem.
-A weight attached to a spring is pulled down 3 inches below the equilibrium position. Assuming that the period of the system is $\frac { 1 } { 5 }$ second, determine a trigonometric model that gives the position of the weight at time $t$ seconds.
A) $\mathrm { s } ( \mathrm { t } ) = 3 \cos \frac { 1 } { 5 } \mathrm { t }$
B) $s ( t ) = 3 \cos 10 \pi t$
C) $s ( t ) = - 3 \cos 5 \pi t$
D) $s ( t ) = - 3 \cos 10 \pi t$

Question

Quizplus · Accepted Answer

The amplitude is 3 inches, and since the weight is pulled down, the cosine function should be negative. The period $T$ is $\frac{1}{5}$ seconds, so the angular frequency $\omega$ is $2\pi \times 5 = 10\pi$. Thus, the model is $s(t) = -3 \cos(10\pi t)$.

Solve the Problem 15\frac { 1 } { 5 }51​ Second, Determine a Trigonometric Model That Gives the Position of Pulled

Solve the Problem $\frac { 1 } { 5 }$ Second, Determine a Trigonometric Model That Gives the Position of Pulled