Find the phase shift of the function.
-$$y = - 2 \sin \left( 2 x - \frac { \pi } { 2 } \right)$$
A) $\frac { \pi } { 4 }$ units to the right
B) $2 \pi$ units down
C) $2 \pi$ units up
D) $\frac { \pi } { 2 }$ units to the left

Question

Quizplus · Accepted Answer

The phase shift of a trigonometric function of the form $y = a \sin(bx - c)$ or $y = a \cos(bx - c)$ is given by $\frac{c}{b}$. Here, $c = \frac{\pi}{2}$ and $b = 2$, so the phase shift is $\frac{\pi/2}{2} = \frac{\pi}{4}$ units to the right.

Find the Phase Shift of the Function y=−2sin⁡(2x−π2)y = - 2 \sin \left( 2 x - \frac { \pi } { 2 } \right)y=−2sin(2x−2π​)

Find the Phase Shift of the Function $y = - 2 \sin \left( 2 x - \frac { \pi } { 2 } \right)$