Find the phase shift of the function.
-$$y = - 3 - 2 \sin \left( 4 x - \frac { \pi } { 3 } \right)$$
A) $\frac { \pi } { 12 }$ units to the left
B) $\frac { \pi } { 6 }$ units to the right
C) $\frac { \pi } { 12 }$ units to the right
D) $\frac { \pi } { 3 }$ units to the left

Question

Quizplus · Accepted Answer

The phase shift is calculated by solving $4x - \frac{\pi}{3} = 0$, giving $x = \frac{\pi}{12}$. Since the coefficient of $x$ is positive, the shift is to the right.

Find the Phase Shift of the Function y=−3−2sin⁡(4x−π3)y = - 3 - 2 \sin \left( 4 x - \frac { \pi } { 3 } \right)y=−3−2sin(4x−3π​)

Find the Phase Shift of the Function $y = - 3 - 2 \sin \left( 4 x - \frac { \pi } { 3 } \right)$