Perform the indicated operations and simplify the result so there are no quotients.
-$\sec \left( 6 \theta + 17 ^ { \circ } \right) = \csc \left( 2 \theta - 7 ^ { \circ } \right)$
A) $\theta = \frac { 17 ^ { \circ } } { 7 }$
B) $\theta = 40 ^ { \circ }$
C) $\theta = 10 ^ { \circ }$
D) $\theta = \frac { 83 ^ { \circ } } { 7 }$

Question

Quizplus · Accepted Answer

The Answer of Perform the indicated operations and simplify the result so there are no quotients.
-$\sec \left( 6 \theta + 17 ^ { \circ } \right) = \csc \left( 2 \theta - 7 ^ { \circ } \right)$
A) $\theta = \frac { 17 ^ { \circ } } { 7 }$
B) $\theta = 40 ^ { \circ }$
C) $\theta = 10 ^ { \circ }$
D) $\theta = \frac { 83 ^ { \circ } } { 7 }$

Perform the Indicated Operations and Simplify the Result So There sec⁡(6θ+17∘)=csc⁡(2θ−7∘)\sec \left( 6 \theta + 17 ^ { \circ } \right) = \csc \left( 2 \theta - 7 ^ { \circ } \right)sec(6θ+17∘)=csc(2θ−7∘)

Perform the Indicated Operations and Simplify the Result So There $\sec \left( 6 \theta + 17 ^ { \circ } \right) = \csc \left( 2 \theta - 7 ^ { \circ } \right)$