Solve the problem.
-Snell's Law states that $$\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } }$$
where $v _ { 1 } , v _ { 2 }$ are the speeds at which light travels through two different mediums, and $\theta _ { 1 } , \theta _ { 2 }$ are the angles of incidence and refraction respectively. Find the angle of refraction if $\frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } } = 1.6$ and the angle of incidence is $26 ^ { \circ }$. Give your answer in degrees to the nearest hundredth.
A) $15.90 ^ { \circ }$
B) $5.24 ^ { \circ }$
C) $7.87 ^ { \circ }$
D) $44.54 ^ { \circ }$

Question

Quizplus · Accepted Answer

Given $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } } = 1.6$ and $\theta _ { 1 } = 26 ^ { \circ }$, we solve for $\theta _ { 2 }$ using Snell's Law. Rearranging the equation and substituting the given values, we find $\sin \theta _ { 2 } = \frac{\sin 26^\circ}{1.6}$. Solving for $\theta _ { 2 }$ yields approximately $15.90 ^ { \circ }$.

Solve the Problem sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } }sinθ2​sinθ1​​=v2​v1​​

Solve the Problem $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } }$