Solve the problem.
-A ship leaves point A and travels directly north to point B. From point B, the ship then travels due east to point C. The magnitude of the vector from point A to point C is 140. Find the magnitude of
The northern vector. Find the magnitude of the eastern vector.
A) $70 \sqrt { 2 }$ north; $70 \sqrt { 2 }$ east
B) 70 north; $70 \sqrt { 3 }$ east
C) $70 \sqrt { 3 }$ north; 70 east
D) 70 north; 70 east

Question

Solve the problem.
-A ship leaves point A and travels directly north to point B. From point B, the ship then travels due east to point C. The magnitude of the vector from point A to point C is 140. Find the magnitude of
The northern vector. Find the magnitude of the eastern vector. 
A) $70 \sqrt { 2 }$ north; $70 \sqrt { 2 }$ east
B) 70 north; $70 \sqrt { 3 }$ east
C) $70 \sqrt { 3 }$ north; 70 east
D) 70 north; 70 east

Quizplus · Accepted Answer

The path from A to C forms a right-angled triangle with the northern and eastern vectors as the legs. Since the magnitude of the vector from A to C is 140, and it forms the hypotenuse of a right-angled triangle, if we assume the legs are equal, then each leg would be $70 \sqrt { 2 }$ because in a 45-45-90 triangle, the legs are $\frac{hypotenuse}{\sqrt{2}}$.

Solve the Problem 70270 \sqrt { 2 }702​ North; 70270 \sqrt { 2 }702​

Solve the Problem $70 \sqrt { 2 }$ North; $70 \sqrt { 2 }$