Solve the problem.
-Two ships leave a harbor together traveling on courses that have an angle of 129° between them. If they each travel 505 miles, how far apart are they (to the nearest mile)?
A)41 mi
B)1824 mi
C)912 mi
D)435 mi

Question

Quizplus · Accepted Answer

Using the law of cosines: c² = a² + b² - 2ab*cos(C), where a = b = 505 miles and C = 129°. Solving gives c ≈ 912 miles.

Solve the Problem. -Two Ships Leave a Harbor Together Traveling on Courses That