Solve the problem.
-A projectile is fired with an initial velocity of 350 feet per second at an angle of 45° with the horizontal. In how many seconds will the projectile strike the ground? (Round your answer to the
Nearest tenth of a second.)
A)23.6 sec
B)15.5 sec
C)20.3 sec
D)12.1 sec

Question

Quizplus · Accepted Answer

The time of flight for a projectile is given by the formula $ t = \frac{2v_0 \sin(\theta)}{g} $, where $ v_0 = 350 $ ft/s, $ \theta = 45^\circ $, and $ g = 32.2 $ ft/s². Plugging in the values, $ t = \frac{2 \times 350 \times \sin(45^\circ)}{32.2} \approx 15.5 $ seconds.

Solve the Problem. -A Projectile Is Fired with an Initial Velocity of 350