Solve the problem.
-Skewness can be measured by Pearson's index of skewness: $$I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$$ If $\mathrm { I } \geq 1.00$ or $\mathrm { I } \leq - 1.00$, the data can be considered significantly skewed. Would you expect that incomes of all adults in the US would be skewed? In which direction? Why? Would you expect that for these incomes, Pearson's index of skewness would be greater than 1 , smaller than $- 1$, or between $- 1$ and 1 ?

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The Answer of Solve the problem.
-Skewness can be measured by Pearson's index of skewness: $$I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$$ If $\mathrm { I } \geq 1.00$ or $\mathrm { I } \leq - 1.00$, the data can be considered significantly skewed. Would you expect that incomes of all adults in the US would be skewed? In which direction? Why? Would you expect that for these incomes, Pearson's index of skewness would be greater than 1 , smaller than $- 1$, or between $- 1$ and 1 ?

Solve the Problem I=3(xˉ− median )sI = \frac { 3 ( \bar { x } - \text { median } ) } { s }I=s3(xˉ− median )​

Solve the Problem $I = \frac { 3 ( \bar { x } - \text { median } ) } { s }$