Find the standard deviation, ?, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth.
-n = 1507; p = .57

A) $\boldsymbol { \sigma } = 19.22$
B) $\boldsymbol { \sigma } = 23.34$
C) $\boldsymbol { \sigma } = 16.81$
D) $\sigma = 22.49$

Question

Find the standard deviation, ?, for the binomial distribution which has the stated values of n and p. Round your answer to the nearest hundredth.
-n = 1507; p = .57

A) $\boldsymbol { \sigma } = 19.22$
B) $\boldsymbol { \sigma } = 23.34$
C) $\boldsymbol { \sigma } = 16.81$
D) $\sigma = 22.49$

Quizplus · Accepted Answer

The standard deviation for a binomial distribution is given by the formula:$\sigma = \sqrt{np(1-p)}$Plugging in the given values, we get:$\sigma = \sqrt{1507 * 0.57 * (1-0.57)} = 19.22$Therefore, the correct answer is A.

Find the Standard Deviation, ?, for the Binomial Distribution Which σ=19.22\boldsymbol { \sigma } = 19.22σ=19.22

Find the Standard Deviation, ?, for the Binomial Distribution Which $\boldsymbol { \sigma } = 19.22$