Solve the problem.
-The probabilities that a batch of 4 computers will contain 0, 1, 2, 3, and 4 defective computers are 0.4521, 0.3970, 0.1307, 0.0191, and 0.0010, respectively. Find the variance for the probability distribution.
A)0.59
B)0.77
C)1.11
D)0.51

Question

Quizplus · Accepted Answer

The variance is calculated using the formula: Var(X) = Σ [P(x) * (x - μ)^2], where μ is the mean. First, calculate the mean μ = Σ [x * P(x)] = 0*0.4521 + 1*0.3970 + 2*0.1307 + 3*0.0191 + 4*0.0010 = 0.7. Then, calculate the variance: Var(X) = (0-0.7)^2*0.4521 + (1-0.7)^2*0.3970 + (2-0.7)^2*0.1307 + (3-0.7)^2*0.0191 + (4-0.7)^2*0.0010 = 0.59.

Solve the Problem. -The Probabilities That a Batch of 4 Computers Will Contain