Solve the problem.
-In a continuous uniform distribution, $$\mu = \frac { \text { minimum } + \text { maximum } } { 2 } \text { and } \sigma = \frac { \text { range } } { \sqrt { 12 } }$$
Find the mean and standard deviation for a uniform distribution having a minimum of $- 2$ and a maximum of 6
A) $\mu = 4 , \sigma = 2.31$
B) $\mu = 2 , \sigma = 1.15$
C) $\mu = 2 , \sigma = 2.31$

Question

Quizplus · Accepted Answer

The mean $\mu = \frac{-2 + 6}{2} = 2$ and the standard deviation $\sigma = \frac{6 - (-2)}{\sqrt{12}} = \frac{8}{\sqrt{12}} = 2.31$.

Solve the Problem μ= minimum + maximum 2 and σ= range 12\mu = \frac { \text { minimum } + \text { maximum } } { 2 } \text { and } \sigma = \frac { \text { range } } { \sqrt { 12 } }μ=2 minimum + maximum ​ and σ=12​ range ​

Solve the Problem $\mu = \frac { \text { minimum } + \text { maximum } } { 2 } \text { and } \sigma = \frac { \text { range } } { \sqrt { 12 } }$