Find the margin of error.
-$$\mathrm { n } = 12 , \overline { \mathrm { x } } = 19.1 , \mathrm {~s} = 5.0,99 \text { percent }$$
A) $14.63

Question

Find the margin of error.
-$$\mathrm { n } = 12 , \overline { \mathrm { x } } = 19.1 , \mathrm {~s} = 5.0,99 \text { percent }$$
A) $14.63 < \mu < 23.57$
B) $14.62 < \mu < 23.58$
C) $14.53 < \mu < 23.67$
D) $15.18 < \mu < 23.02$

Quizplus · Accepted Answer

The margin of error is calculated using the formula: $ ME = t^* \times \frac{s}{\sqrt{n}} $. For a 99% confidence level and $ n = 12 $, the t-value is approximately 3.106. Thus, $ ME = 3.106 \times \frac{5}{\sqrt{12}} \approx 4.48 $. The confidence interval is $ 19.1 \pm 4.48 $, which gives $ 14.62 < \mu < 23.58 $.

Find the Margin of Error n=12,x‾=19.1, s=5.0,99 percent \mathrm { n } = 12 , \overline { \mathrm { x } } = 19.1 , \mathrm {~s} = 5.0,99 \text { percent }n=12,x=19.1, s=5.0,99 percent

Find the Margin of Error $\mathrm { n } = 12 , \overline { \mathrm { x } } = 19.1 , \mathrm {~s} = 5.0,99 \text { percent }$