An ideal $10.0 - \mathrm { V }$ dc is connected across a $590.0 - \Omega$, resistor in series with an $840.0 - \Omega$ resistor. What is the potential drop across the $590.0 \Omega$ resistor?
A) $4.1 \mathrm {~V}$
B) $14 \mathrm {~V}$
C) $7.0 \mathrm {~V}$
D) $5.9 \mathrm {~V}$

Question

Quizplus · Accepted Answer

The total resistance in the series circuit is $590.0 \Omega + 840.0 \Omega = 1430.0 \Omega$. The current through the circuit is $I = V / R = 10.0 \, \text{V} / 1430.0 \, \Omega = 0.007 \, \text{A}$. The potential drop across the $590.0 \Omega$ resistor is $V = I \times R = 0.007 \, \text{A} \times 590.0 \, \Omega = 4.13 \, \text{V}$, which rounds to $4.1 \, \text{V}$.

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