A15- $\Omega$ resistor is connected in parallel with a $30 - \Omega$ resistor. If this combination is now connected in series with an ideal $9.0 - \mathrm { V }$ battery and a $20 - \Omega$ resistor, what is the current through the $15 - \Omega$ resistor?
A) $0.20 \mathrm {~A}$
B) $0.26 \mathrm {~A}$
C) $0.10 \mathrm {~A}$
D) $0.13 \mathrm {~A}$

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The Answer of A15- $\Omega$ resistor is connected in parallel with a $30 - \Omega$ resistor. If this combination is now connected in series with an ideal $9.0 - \mathrm { V }$ battery and a $20 - \Omega$ resistor, what is the current through the $15 - \Omega$ resistor?
A) $0.20 \mathrm {~A}$
B) $0.26 \mathrm {~A}$
C) $0.10 \mathrm {~A}$
D) $0.13 \mathrm {~A}$

A15- Ω\OmegaΩ Resistor Is Connected in Parallel with A 30−Ω30 - \Omega30−Ω

A15- $\Omega$ Resistor Is Connected in Parallel with A $30 - \Omega$