A 200- $\Omega$ resistor, a $40 - \mathrm { mH }$ inductor, and a $2.0 - \mu \mathrm { F }$ capacitor are connected in series with a $120 - \mathrm { V }$ rms source at $1.0 \mathrm { kH }$. What is the phase angle of this circuit?
A) $90 ^ { \circ }$
B) $49 ^ { \circ }$
C) $41 ^ { \circ }$
D) $0 ^ { \circ }$
E) $45 ^ { \circ }$

Question

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The Answer of A 200- $\Omega$ resistor, a $40 - \mathrm { mH }$ inductor, and a $2.0 - \mu \mathrm { F }$ capacitor are connected in series with a $120 - \mathrm { V }$ rms source at $1.0 \mathrm { kH }$. What is the phase angle of this circuit?
A) $90 ^ { \circ }$
B) $49 ^ { \circ }$
C) $41 ^ { \circ }$
D) $0 ^ { \circ }$
E) $45 ^ { \circ }$

A 200- Ω\OmegaΩ Resistor, A 40−mH40 - \mathrm { mH }40−mH Inductor, and A

A 200- $\Omega$ Resistor, A $40 - \mathrm { mH }$ Inductor, and A