At what frequency will a $14.0 - \mathrm { mH }$ coil have $14.0 \Omega$ of inductive reactance?
A) $505 \mathrm {~Hz}$
B) $257 \mathrm {~Hz}$
C) $159 \mathrm {~Hz}$
D) $1000 \mathrm {~Hz}$

Question

Quizplus · Accepted Answer

The inductive reactance $X_L$ is given by $X_L = 2\pi fL$, where $f$ is the frequency in hertz, $L$ is the inductance in henries. Rearranging for $f$, we get $f = \frac{X_L}{2\pi L}$. Substituting $X_L = 14.0 \Omega$ and $L = 14.0 \times 10^{-3} \, \text{H}$, we find $f = \frac{14.0}{2\pi \times 14.0 \times 10^{-3}} \approx 159 \, \text{Hz}$.

At What Frequency Will A 14.0−mH14.0 - \mathrm { mH }14.0−mH

At What Frequency Will A $14.0 - \mathrm { mH }$