An object is undergoing simple harmonic motion of amplitude 2.3 m. If the maximum velocity of the object is 10 m/s, what is the object's angular frequency?
A) 4.8 rad/s
B) 4.0 rad/s
C) 3.5 rad/s
D) 4.3 rad/s

Question

Quizplus · Accepted Answer

The maximum velocity $v_{max}$ in simple harmonic motion is given by the formula $v_{max} = \omega A$, where $\omega$ is the angular frequency and $A$ is the amplitude. Rearranging for $\omega$, we get $\omega = \frac{v_{max}}{A}$. Substituting the given values, $\omega = \frac{10 \, \text{m/s}}{2.3 \, \text{m}} = 4.3478 \, \text{rad/s}$, which rounds to $4.3 \, \text{rad/s}$.

An Object Is Undergoing Simple Harmonic Motion of Amplitude 2