During each cycle of operation, a refrigerator absorbs 230 J of heat from the freezer and expels 356 J of heat to the room. How much work input is required in each cycle?
A) 586 J
B) 126 J
C) 712 J
D) 460 J

Question

Quizplus · Accepted Answer

The work input required for each cycle can be calculated using the first law of thermodynamics, which in the context of a refrigerator is often simplified to the equation: Work input = Heat expelled - Heat absorbed. Therefore, the work input is 356 J - 230 J = 126 J.

During Each Cycle of Operation, a Refrigerator Absorbs 230 J