An ideal transformer consists of a 500-turn primary coil and a 2000-turn secondary coil. If the current in the secondary is 3.0 A, what is the current in the primary?
A) 0.75 A
B) 48 A
C) 12 A
D) 1.3 A

Question

Quizplus · Accepted Answer

The current in the primary coil can be found using the transformer equation $I_p = \frac{N_s}{N_p} \times I_s$, where $I_p$ is the primary current, $N_s$ and $N_p$ are the number of turns in the secondary and primary coils, respectively, and $I_s$ is the secondary current. Substituting the given values, $I_p = \frac{2000}{500} \times 3.0 A = 4 \times 3.0 A = 12 A$.

An Ideal Transformer Consists of a 500-Turn Primary Coil and a 2000-Turn