In the figure, a small particle of charge $- 1.9 \times 10 ^ { - 6 } \mathrm { C }$ and mass $m = 3.1 \times 10 ^ { - 12 } \mathrm {~kg}$ has speed $v _ { 0 } = 8.1 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }$ as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed to travel in the semicircular path shown with radius $R = 5.0 \mathrm {~cm}$. Find the magnitude and direction of the magnetic field in the region.

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The Answer of In the figure, a small particle of charge $- 1.9 \times 10 ^ { - 6 } \mathrm { C }$ and mass $m = 3.1 \times 10 ^ { - 12 } \mathrm {~kg}$ has speed $v _ { 0 } = 8.1 \times 10 ^ { 3 } \mathrm {~m} / \mathrm { s }$ as it enters a region of uniform magnetic field. The particle is initially traveling perpendicular to the magnetic field and is observed to travel in the semicircular path shown with radius $R = 5.0 \mathrm {~cm}$. Find the magnitude and direction of the magnetic field in the region.

In the Figure, a Small Particle of Charge −1.9×10−6C- 1.9 \times 10 ^ { - 6 } \mathrm { C }−1.9×10−6C

In the Figure, a Small Particle of Charge $- 1.9 \times 10 ^ { - 6 } \mathrm { C }$