In a two-slit experiment, monochromatic coherent light of wavelength $600 \mathrm {~nm}$ passes through a pair of slits separated by $2.20 \times 10 ^ { - 5 } \mathrm {~m}$. At what angle away from the centerline does the second dark fringe occur?
A) $1.17 ^ { \circ }$
B) $3.51 ^ { \circ }$
C) $2.34 ^ { \circ }$
D) $3.94 ^ { \circ }$
E) $4.70 ^ { \circ }$

Question

Quizplus · Accepted Answer

The angle for the second dark fringe in a two-slit experiment can be found using the formula for destructive interference, $d \sin \theta = (m + \frac{1}{2})\lambda$, where $d$ is the slit separation, $\lambda$ is the wavelength of the light, and $m$ is the order number of the dark fringe (starting from 0). For the second dark fringe, $m = 1$. Plugging in the given values: $2.20 \times 10^{-5} \sin \theta = (1 + \frac{1}{2})(600 \times 10^{-9})$, solving for $\theta$ gives an angle close to $2.34^\circ$.

In a Two-Slit Experiment, Monochromatic Coherent Light of Wavelength 600 nm600 \mathrm {~nm}600 nm

In a Two-Slit Experiment, Monochromatic Coherent Light of Wavelength $600 \mathrm {~nm}$